3y+5y(y-3)=5y^2+12

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Solution for 3y+5y(y-3)=5y^2+12 equation: 


Simplifying
3y + 5y(y + -3) = 5y2 + 12

Reorder the terms:
3y + 5y(-3 + y) = 5y2 + 12
3y + (-3 * 5y + y * 5y) = 5y2 + 12
3y + (-15y + 5y2) = 5y2 + 12

Combine like terms: 3y + -15y = -12y
-12y + 5y2 = 5y2 + 12

Reorder the terms:
-12y + 5y2 = 12 + 5y2

Add '-5y2' to each side of the equation.
-12y + 5y2 + -5y2 = 12 + 5y2 + -5y2

Combine like terms: 5y2 + -5y2 = 0
-12y + 0 = 12 + 5y2 + -5y2
-12y = 12 + 5y2 + -5y2

Combine like terms: 5y2 + -5y2 = 0
-12y = 12 + 0
-12y = 12

Solving
-12y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-12'.
y = -1

Simplifying
y = -1

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